Christos Hatzis escribió:
> Use a list to store the partial matrices:
>
> z <- vector("list", 189)
>
> for(i in 1:189)
> z[[i]] <- subset(...)
>
Hi Christos,
I've tried it but it died unexpectedly with a (Killed) message and the
linux console prompt again. I think I have enough memory (512) and a
pretty good processor (P4, 2.8)
Antonio
> -Christos
>
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of antonio rodriguez
> Sent: Tuesday, November 07, 2006 2:01 PM
> To: R-Help
> Subject: [R] subsetting a matrix and filling other
>
> Hi,
>
> Having a matrix F(189,6575) I want to do this:
>
> z1<-subset(F[,1], F[,1] >= 5 & F[,1] <= 10) .
> .
> .
> z189<-subset(F[,189], F[,189] >= 5 & F[,189] <= 10)
>
> I would prefer to have an empty matrix, say 'z' in order to fill its columns
> with the output of subsetting F. But each of the subsets can differ in
> length. It's to say:
>
> length(z1)
> 1189
>
> length(z2)
> 1238
>
> Don't know how to set up this with a for loop or the use of apply:
>
> z<-189
> for (i in 1:189)
> {z[i]<-subset(F.zoo[,i], F.zoo[,i] >= 5 & z1 <= 10)}
>
> Error in z[i] <- subset(F.zoo[, i], F.zoo[, i] >= 5 & z1 <= 10) :
> nothing to replace with
>
> or
>
> z<-matrix(0,6575,189)
> for (i in 1:189)
> {z[i]<-subset(F.zoo[,i], F.zoo[,i] >= 5 & z1 <= 10)}
>
> new error
>
>
> Thanks,
>
> Antonio
>
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>
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