Hi
gregexpr can be used
bits <-"0011011aaa0"
gregexpr("[01]", bits)
[[1]]
[1] 1 2 3 4 5 6 7 11
attr(,"match.length")
[1] 1 1 1 1 1 1 1 1
or
grep("[^01]", bits)
if you want to know that there is any other character then 0 or 1
gregexpr("1", bits)
if you want to know location of 1's
HTH
Petr
On 29 Nov 2006 at 15:06, Carmen Meier wrote:
Date sent: Wed, 29 Nov 2006 15:06:08 +0100
From: Carmen Meier <[EMAIL PROTECTED]>
To: R-help <r-help@stat.math.ethz.ch>
Subject: [R] String question
> Hi to all
> I would to determinate whether bits is a binary code and I would to
> find out the which bit is set to 1
>
> bits <-"00110110"
> I found to detect whether there are only numbers
> all.digits(bits)
> but is there any function to detect whether there are only 0 and 1 in
> the string
>
> And how could I get the f.e the third "bit" from the right hand side
>
> With regards Carmen
>
> ______________________________________________
> R-help@stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html and provide commented,
> minimal, self-contained, reproducible code.
Petr Pikal
[EMAIL PROTECTED]
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