Sorry, you wanted or, not and. with(foo, pmax(x < y, x > z))
with(foo, as.numeric(x < y | x > z)) with(foo, 1*(x < y | x > z)) On 5/10/07, Gabor Grothendieck <[EMAIL PROTECTED]> wrote: > or > > with(foo, (x < y) * (x > z)) > > On 5/10/07, jim holtman <[EMAIL PROTECTED]> wrote: > > You don't need apply. Just do > > > > foo$result <- ifelse((foo$x < foo$y) | (foo$x > foo$z), 1, 0) > > > > On 5/10/07, Greg Tarpinian <[EMAIL PROTECTED]> wrote: > > > I have a question that must have a simple answer (but eludes me). > > > I need a row-by-row logical comparison across three numeric variables > > > in > > > a data frame: foo$x, foo$y, foo$z. The logic is > > > > > > if( x < y || x > z ) 1 else 0 > > > > > > for a particular row. > > > > > > It is simple and very inefficient to use for(i in 1:length(foo$x)){ } > > > loops. How can I accomplish this using sappy( ) / lapply( ) / apply( ) > > > or some other more efficient method? > > > > > > Thank you in advance, > > > > > > Greg > > > > > > ______________________________________________ > > > R-help@stat.math.ethz.ch mailing list > > > https://stat.ethz.ch/mailman/listinfo/r-help > > > PLEASE do read the posting guide > > > http://www.R-project.org/posting-guide.html > > > and provide commented, minimal, self-contained, reproducible code. > > > > > > > > > -- > > Jim Holtman > > Cincinnati, OH > > +1 513 646 9390 > > > > What is the problem you are trying to solve? > > > > ______________________________________________ > > R-help@stat.math.ethz.ch mailing list > > https://stat.ethz.ch/mailman/listinfo/r-help > > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > > and provide commented, minimal, self-contained, reproducible code. > > > ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.