Thanks for the suggestion. However, I've tried sapply and data.matrix.
The problem is that it while it returns a numeric matrix, it gives back: 1 1 1 2 2 2 3 3 3 instead of 1 2 3 4 5 6 7 8 9 The latter matrix is the desired result Thanks, Andrew On 5/16/07, Marc Schwartz <[EMAIL PROTECTED]> wrote: > > On Wed, 2007-05-16 at 08:40 -0400, Andrew Yee wrote: > > Thanks for the suggestion and the explanation for why I was running > > into these troubles. > > > > I've tried: > > > > as.numeric(as.matrix(sample.data[-1, -1])) > > > > However, this creates another vector rather than a matrix. > > Right. That's because I'm an idiot and need more caffeine... :-) > > > Is there a straight forward way to convert this directly into a > > numeric matrix rather than a vector? > > Yeah, Dimitris' approach below of using data.matrix(). > > You could also use: > > mat <- sapply(sample.data[-1, -1], as.numeric) > rownames(mat) <- rownames(sample.data[-1, -1]) > > > mat > x y z > 2 1 1 1 > 3 2 2 2 > 4 3 3 3 > > Though, this is essentially what data.matrix() does internally. > > > Additionally, I've also considered: > > > > data.matrix(sample.data[-1,-1] > > > > but bizarrely, it returns: > > > > x y z > > 2 1 1 1 > > 3 2 2 2 > > 4 3 3 3 > > That is a numeric matrix: > > > str(data.matrix(sample.data[-1, -1])) > int [1:3, 1:3] 1 2 3 1 2 3 1 2 3 > - attr(*, "dimnames")=List of 2 > ..$ : chr [1:3] "2" "3" "4" > ..$ : chr [1:3] "x" "y" "z" > > HTH, > > Marc > > > > > Thanks, > > Andrew > > > > > > On 5/16/07, Marc Schwartz <[EMAIL PROTECTED]> wrote: > > On Wed, 2007-05-16 at 08:10 -0400, Andrew Yee wrote: > > > I have the following csv file: > > > > > > name,x,y,z > > > category,delta,gamma,epsilon > > > a,1,2,3 > > > b,4,5,6 > > > c,7,8,9 > > > > > > I'd like to create a numeric matrix of just the numbers in > > this csv dataset. > > > > > > I've tried the following program: > > > > > > sample.data <- read.csv("sample.csv") > > > numerical.data <- as.matrix(sample.data[-1,-1]) > > > > > > However, print(numerical.data ) returns what appears to be a > > matrix of > > > characters: > > > > > > x y z > > > 2 "1" "2" "3" > > > 3 "4" "5" "6" > > > 4 "7" "8" "9" > > > > > > How do I force it to be numbers rather than characters? > > > > > > Thanks, > > > Andrew > > > > The problem is that you have two rows which contain alpha > > entries. > > > > The first row is treated as the header, but the second row is > > treated as > > actual data, thus overriding the numeric values in the > > subsequent rows. > > > > You could use: > > > > as.numeric(as.matrix(sample.data[-1, -1])) > > > > to coerce the matrix to numeric, or if you don't need the > > alpha entries, > > you could modify the read.csv() call to something like: > > > > read.csv("sample.csv", header = FALSE, skip = 2, row.names = > > 1, > > col.names = c("name", "x", "y", "z") > > > > This will skip the first two rows, set the first column to the > > row names > > and give you a data frame with numeric columns, which in most > > cases can > > be treated as a numeric matrix and/or you could explicitly > > coerce it to > > one. > > > > HTH, > > > > Marc Schwartz > > > > > > > > [[alternative HTML version deleted]] ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.