Try this and see the help desk article in R News 4/1: > x <- 20080620.00 > x2 <- 20090218.00 > num2Date <- function(x) as.Date(paste(x), "%Y%m%d") > num2Date(x2) - num2Date(x) Time difference of 243 days > as.numeric(num2Date(x2) - num2Date(x)) [1] 243
On 6/20/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote: > Dear R users, > > I have a problem computing time differences using R. > > I have a date that are given using the following format: 20080620.00, where > the 4 first digits represent the year, the next 2 ones the month and the last > 2 ones the day. I would need to compute time differences between two vectors > of this given format. > > I tried around trying to change this format into any type of time serie > without any succes. > > Could some one provide me with some useful suggestion and/or tip to know > where to look? > > I am using R-2.4.0 under Windows XP > > Thanks for your help, > > Vincent > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.