On Fri, 13 Jul 2007, David Barron wrote: > Try having a look at the scale and sweep functions.
sweep applies to arrays, not data frames, and scale converts to a matrix. For a data frame df2 <- df1 df2[] <- lapply(df1, function(x) {r <- range(x, na.rm=TRUE); (x-r[1])/diff(r)}) seems simple enough. > On 13/07/07, Amir_17 <[EMAIL PROTECTED]> wrote: >> Hi >> I have dataframe which contain 5 columns and 1000 records. I want standard >> each cell. >> I want range each column between 0 and 1 . I think i must use loop? >> could you help me? -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UK Fax: +44 1865 272595 ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.