> x = matrix(rnorm(9),3)
> x
[,1] [,2] [,3]
[1,] 1.29693748 0.2018959 0.02534092
[2,] -1.19468858 -1.2249229 -0.85948508
[3,] -0.09274508 0.4071841 -0.11481410
> apply(x,1,which.min)
[1] 3 2 3
On 8/20/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
>
> One more question. After I collapse everything into one matrix, I would
> like to find the index of column that holds minimum value for each row. I
> remember that there is a function like maxCols but I can't seem to find the
> same thing for minimum value. Any suggestion please?
>
> - adschai
>
>
> ----- Original Message -----From: Gabor Grothendieck Date: Sunday, August
> 19, 2007 8:48 pmSubject: Re: [R] how to collapse a list of 1 column matrix
> to a matrix?To: "[EMAIL PROTECTED]" Cc: r-help@stat.math.ethz.ch> Try
> this:> > L <- list(`1` = matrix(1:4, 4), `2` = matrix(5:8, 4))> sapply(L,
> c)> > Note that the list component names are kept as column names in > the
> result> > > On 8/19/07, [EMAIL PROTECTED] wrote:> > Hi,> >> > I
> encounter a situation where I have a list whose element is a > column
> matrix. Says,> >> > $'1'> > [,1]> > 1> > 2> > 3> >> > $'2'> > [,1]> > 4> >
> 5> > 6> >> > Is there fast way to collapse the list into a matrix like a >
> cbind operation in this case? Meaning, the result should be a > matrix that
> looks like:> >> > [,1] [,2]> > [1,] 1 4> > [2,] 2 5> >
> [3,] 3 6> >> > I can loop through all elements and do cbind
> manually. But I > think there must be a simpler way that I don't know. Thank
> you.> >> > - adschai> >> > __!
> ____________________________________________> > [EMAIL PROTECTED] list> >
> https://stat.ethz.ch/mailman/listinfo/r-help> > PLEASE do read the posting
> guide http://www.R-> project.org/posting-guide.html> > and provide
> commented, minimal, self-contained, reproducible code.> >>
>
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