On Tue, 21 Aug 2007, Todd Remund wrote:
> I have a zoo object for which I would like to subset using a vector of time
> values. For example, I have the following time values represented in my zoo
> object.
>
> -50.000 -49.996 -49.995 -49.960 -49.956 -49.955 -49.920 -49.916 -49.915
> -49.880
>
> and would like to get observations corresponding to times
>
> -50 -49.96 -49.92 -49.88.
>
> What can I do without using the lapply or which functions?
Use the window() function:
z <- zoo(1:10, c(-50.000, -49.996, -49.995, -49.960, -49.956, -49.955,
-49.920, -49.916, -49.915, -49.880))
window(z, c(-50, -49.96, -49.92, -49.88))
hth,
Z
> Thank you.
>
> Todd Remund
>
> ______________________________________________
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
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and provide commented, minimal, self-contained, reproducible code.
