Hello,
This message isn't directly related to finance for it just uses the problem
at hand contextually under the crypto domain. Thus, I have a data frame
made from exchanges' names and the intervals each exchange provides. See
below, please.
exchanges.names <- c('binance', 'bitmart', 'bybit', 'crypto.com', 'huobi',
'kraken', 'kucoin', 'mexc')
intervals <- list(list('1s', '1m', '3m', '5m', '15m', '30m', '1h', '2h',
'4h', '6h', '8h', '12h', '1d', '3d', '1w', '1M'),
list('1m', '3m', '5m', '15m', '30m', '1h', '2h', '4h',
'6h', '12h', '1d', '3d', '1w'),
list('1m', '3m', '5m', '15m', '30m', '1h', '2h',
'4h','6h', '12h', '1d', '1M', '1w'),
list('1m', '5m', '15m', '30m', '1h', '2h', '4h', '12h',
'1d', '1w', '2w', '1M'),
list('1m', '5m', '15m', '30m', '1h', '4h', '1d', '1w',
'1M'),
list('1m', '5m', '15m', '30m', '1h', '4h', '12h', '1d',
'1w'),
list('1m', '5m', '15m', '30m', '1h', '2h', '4h', '8h',
'12h', '1d', '1w'),
list('1m', '5m', '15m', '30m', '1h', '4h', '8h', '1d',
'1w', '1M')
)
exchanges.intervals <- as.data.frame(cbind(exchanges.names, intervals))
exchanges.intervals
exchanges.names intervals
1 binance 1s, 1m, 3m, 5m, 15m, 30m, 1h, 2h, 4h, 6h, 8h, 12h, 1d,
3d, 1w, 1M
2 bitmart 1m, 3m, 5m, 15m, 30m, 1h, 2h, 4h, 6h, 12h, 1d, 3d, 1w
3 bybit 1m, 3m, 5m, 15m, 30m, 1h, 2h, 4h, 6h, 12h, 1d, 1M, 1w
4 crypto.com 1m, 5m, 15m, 30m, 1h, 2h, 4h, 12h, 1d, 1w, 2w, 1M
5 huobi 1m, 5m, 15m, 30m, 1h, 4h, 1d, 1w, 1M
6 kraken 1m, 5m, 15m, 30m, 1h, 4h, 12h, 1d, 1w
7 kucoin 1m, 5m, 15m, 30m, 1h, 2h, 4h, 8h, 12h, 1d, 1w
8 mexc 1m, 5m, 15m, 30m, 1h, 4h, 8h, 1d, 1w, 1M
Suppose now I want to get the 5m interval from the binance exchange. While
I can filter the binance row with,
exchanges.intervals[exchanges.names == "binance", ]
exchanges.names
intervals
1 binance 1s, 1m, 3m, 5m, *15m*, 30m, 1h, 2h, 4h, 6h, 8h, 12h, 1d,
3d, 1w, 1M
I don't know how get the fourth element date from the filtered data frame
nested list. I need to use its data content.
Any help appreciated!
TIA,
--
André Luiz Tietbohl Ramos, PhD
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