Dear Edzer,

sorry for bothering you once more but I need to be sure about my R script.

In summary, i'm comparing the performance of regression-kriging and collocated co-kriging.

Regression-kriging was based on an unique covariate, the elevation Z.

I use Z as unique ancillary variable in the Co-kriging.

As first attempt, the final raster maps were completely different. It appeared that it was due

to the fact that the dataset was non-stationary and only regression-kriging overcomes this issue, while co-kriging not.

But if I pass to universal co-kriging introducing Z as covariate, it bacomes useless as ancillary variable!

What is my mistake?

emanuele




Il 2019-08-15 12:00 r-sig-geo-requ...@r-project.org ha scritto:
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Today's Topics:

   1. Error running codes (Enoch Gyamfi Ampadu)
   2. Re: regression-kriging and co-kriging (Edzer Pebesma)

----------------------------------------------------------------------

Message: 1
Date: Thu, 15 Aug 2019 06:51:49 +0200
From: Enoch Gyamfi Ampadu <egamp...@gmail.com>
To: r-sig-geo@r-project.org
Subject: [R-sig-Geo] Error running codes
Message-ID:
        <cac4+n+yravrhc_mcoatv-ao_-sh7qyo8zukzaojqbnabgjx...@mail.gmail.com>
Content-Type: text/plain; charset="utf-8"

Dear List,

Please I have been running a certain the codes below to read my image,
shapeffile to enable me classify for cover with Random forest. I have
gotten to the point of extracting the raster values and the raster
information. However I keep getting errors. though I have tried different
combination and other codes like readOGR for importing the training
polygon. I will be glad if you could be of help as I am new to using R.

#import clip image of study area

TestImg3 <- brick("C:\\Users\\hp\\Desktop\\Data collection\\Nkandla
Images\\Landsat\\2019\\08052019\\Corrected\\New
Folder\\Image08052019_Clip.tif")

#Assign name of bands
names(TestImg3) <- c(paste0("B", 1:7, coll=""), "B9")
plotRGB(TestImg3, r=4, g=3, b=2, stretch ="lin")

#Import training shapefile
sample <- shapefile("C:/Users/hp/Desktop/Data collection/Nkandla
Images/Landsat/2019/08052019/Corrected/Train08052019_2.shp")

responseCol <- "class"

#(I have tried options of changing "class" to "classname" as reflect actaul
name assigned in ArcMap)

# Overlap the sample polygons on the image (combine the class information
with extracted values).

pixels = data.frame(matrix(vector(), nrow = 0, ncol = length(names(img)) +
1))
for (i in 1:length(unique(sample[[responseCol]]))){
  category <- unique(sample[[responseCol]])[i]
  categorymap <- sample[sample[[responseCol]] == category,]
  dataSet <- extract(img, categorymap)
  dataSet <- dataSet[!unlist(lapply(dataSet, is.null))]
  if(is(sample, "SpatialPointsDataFrame")){
    dataSet <- cbind(dataSet, class = as.numeric(category))
    pixeles <- rbind(pixeles, dataSet)
  }
  if(is(sample, "SpatialPolygonsDataFrame")){
    dataSet <- lapply(dataSet, function(x){cbind(x, class =
as.numeric(rep(category,

 nrow(x))))})
    df <- do.call("rbind", dataSet)
    pixels <- rbind(pixeles, df)
  }

}

THIS IS THE ERROR I GET FROM RUNNING THE ABOVE CODES

for (i in 1:length(unique(samples[[responseCol]]))){
+   category <- unique(samples[[responseCol]])[i]
+   categorymap <- samples[samples[[responseCol]] == category,]
+   dataSet <- extract(img, categorymap)
+
+   if(is(sample, "SpatialPointsDataFrame")){
+     dataSet <- cbind(dataSet, class = as.numeric(category))
+     pixeles <- rbind(pixeles, dataSet)
+   }
+   if(is(sample, "SpatialPolygonsDataFrame")){
+     dataSet <- lapply(dataSet, function(x){cbind(x, class =
as.numeric(rep(category,
+
  nrow(x))))})
+     df <- do.call("rbind", dataSet)
+     pixels <- rbind(pixeles, df)
+   }
+
+ }
Error in y[i, ] :
  cannot get a slot ("Polygons") from an object of type "NULL"


Please help me out.
Thank you.

Best regards,

Enoch

--
*Enoch Gyamfi - Ampadu*

*Geography & Environmental Sciences*

*College of Agriculture, Engineering & Science*

*University of KwaZulu-Natal, Westville Campus*

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------------------------------

Message: 2
Date: Thu, 15 Aug 2019 08:33:59 +0200
From: Edzer Pebesma <edzer.pebe...@uni-muenster.de>
To: r-sig-geo@r-project.org
Subject: Re: [R-sig-Geo] regression-kriging and co-kriging
Message-ID: <bdae5226-7023-7e30-1927-5fb66ff41...@uni-muenster.de>
Content-Type: text/plain; charset="utf-8"



On 8/12/19 8:21 PM, Emanuele Barca wrote:
Dear Edzer,

maybe I found the solution. I found this in the predict function help:
"When a non-stationary (i.e., non-constant) mean is used, both for
simulation and prediction purposes the variogram model defined should be
that of the residual process, and not that of the raw observations"
Since my data were, actually, non-stationary, I applied the universal
co-kriging instead usual co-kriging.
now the maps of regression-kring and co-kriging are actually similar s
expected.
did I understand correctly the quoted sentence?

I think so, but hard to be sure given the information you provide.


regards

emanuele barca
------------------------------

Message: 2
Date: Sat, 10 Aug 2019 10:41:38 +0200
From: Edzer Pebesma <edzer.pebe...@uni-muenster.de>
To: r-sig-geo@r-project.org
Subject: Re: [R-sig-Geo] regression-kriging and co-kriging
Message-ID: <da76da51-e46b-8a8d-4952-7c3b85c19...@uni-muenster.de>
Content-Type: text/plain; charset="utf-8"

Hard to tell from your script. Maybe give a reproducible example?

On 8/6/19 1:07 PM, Emanuele Barca wrote:
Dear  r-sig-geo friends,

I produced two maps garnered in the following way:

# for regression-kriging
Piezo.map <-autoKrige(LivStat ~  Z, input_data = mydata.sp, new_data
= covariates,  model = "Ste")

Piezork.pred <- Piezo.map$krige_output$var1.pred
Piezork.coords <- Piezo.map$krige_output@coords
Piezork.out <- as.data.frame(cbind(Piezork.coords, Piezork.pred))
colnames(Piezork.out)[1:2] <- c("X", "Y")
coordinates(Piezork.out) = ~ X + Y
gridded(Piezork.out) <- TRUE

spplot(Piezork.out, main = list(label = "R-k Hydraulic head", cex =
1.5))

#for co-kriging
g <- gstat(id = "Piezo", formula = LivStat ~ 1, data = mydata.sp, set
= list(nocheck = 1))
g <- gstat(g, id = "Z", formula = Z ~ 1, data = mydata.sp, set =
list(nocheck = 1))

v.g <- variogram(g)

#g <- gstat(g, id = "Piezo", model = vgm(150, "Mat", 1350, 0.0, kappa
= 1.9), fill.all = T)#
g <- gstat(g, id = "Piezo", model = vgm(0.7, "Ste", 1300, 18, kappa =
1.9), fill.all = T)#
g.fit <- fit.lmc(v.g, g, fit.lmc = TRUE, correct.diagonal = 1.01) #
fit multivariable variogram model , fit.lmc = TRUE, correct.diagonal
= 1.01
g.fit
plot(v.g, model = g.fit, main = "Fitted Variogram Models - Raw Data")#
#gridded(covariates) <- TRUE
g.cok <- predict(g.fit, newdata = covariates)#grid

g.cok.pred <- g.cok@data$Piezo.pred
aaaa <- na.omit(g.cok.pred)
g.cok.coords <- g.cok@coords
g.cok.out <- as.data.frame(cbind(g.cok.coords, g.cok.pred))
colnames(g.cok.out)[1:2] <- c("X", "Y")
coordinates(g.cok.out) = ~ X + Y
gridded(g.cok.out) <- TRUE
spplot(g.cok.out, main = list(label = "Hydraulic head with
Co-kriging", cex = 1.5))

###########################################################################################################################


I am unable to understand why the first map appears as a raster and
the second not, notwithstanding the fact that they are both computed
on the same "covariates" DEM???

where is the mistake???

regards

emanuele

________________________________________________________
Emanuele Barca                               Researcher
Water Research Institute                       (IRSA-CNR)
Via De Blasio, 5                       70123 Bari (Italy)
Phone +39 080 5820535               Fax  +39 080 5313365
Mobile +39 340 3420689
_________________________________________________________



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Edzer Pebesma
Institute for Geoinformatics
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