Dear Thierry,
Thanks very much. This was helpful. The code work with some changes.
Tord
ONKELINX, Thierry wrote:
Dear Tord,
You need to supply the datavalues to the pretty function. An untested example
as your example was not reproducible with a (dummy) dataset.
PrettyBreaks <- pretty(as.vector(resdf[,c("TempEst.t","TempEst.tM1")]))
spplot(SpatialPolygonsDataFrame(karta,
as.data.frame(resdf[,c("TempEst.t","TempEst.tM1")])),at=PrettyBreaks)
HTH,
Thierry
----------------------------------------------------------------------------
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
Cel biometrie, methodologie en kwaliteitszorg / Section biometrics, methodology
and quality assurance
Gaverstraat 4
9500 Geraardsbergen
Belgium
tel. + 32 54/436 185
[EMAIL PROTECTED]
www.inbo.be
To call in the statistician after the experiment is done may be no more than
asking him to perform a post-mortem examination: he may be able to say what the
experiment died of.
~ Sir Ronald Aylmer Fisher
The plural of anecdote is not data.
~ Roger Brinner
The combination of some data and an aching desire for an answer does not ensure
that a reasonable answer can be extracted from a given body of data.
~ John Tukey
-----Oorspronkelijk bericht-----
Van: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Namens Tord Snäll
Verzonden: vrijdag 14 november 2008 12:14
Aan: r-sig-geo@stat.math.ethz.ch
Onderwerp: [R-sig-Geo] pretty in spplot()
Dear all,
I would like legend cut-offs that are prettier that just executing
spplot(SpatialPolygonsDataFrame(karta,
as.data.frame(resdf[,c("TempEst.t","TempEst.tM1")])))
I try
spplot(SpatialPolygonsDataFrame(karta,
as.data.frame(resdf[,c("TempEst.t","TempEst.tM1")])),at=pretty())
, though without sucess.
Could someone give a clue on how to do it?
Thanks!
/Tord
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