Thanks Jorge, you answered my generic R question! Cheers,
Felipe On Feb 21, 2010, at 1:21 AM, Jorge Ivan Velez wrote: > Hi Felipe, > > Try this: > > m1 <- matrix(c(0, 1, 2, > 1, 0, 3, > 2, 3, 0), 3,3) > m1 > > m2 <- matrix(c(0, 4, 5, > 4, 0, 6, > 5, 6, 0), 3,3) > m2 > > m3 <- matrix(0, 3, 3) > m3[lower.tri(m3)] <- m1[lower.tri(m1)] > m3[t(lower.tri(m3))] <- m2[t(lower.tri(m1))] > m3 > > HTH, > Jorge > > On Sun, Feb 21, 2010 at 2:02 AM, Felipe Zapata <> wrote: > A general question for R users about matrix manipulation: > > I have two symmetric distance matrices (measuring distances in 2 > different variables) and I am trying to build a new matrix showing > one half of one of the matrices (below diagonal) and the other half > of other matrix (above he diagonal). Is there any R function to do > this?? any help would be appreciated. > > This is what i am talking about > > The matrices I have: > > matrix 1: > [1] [2] [3] > [1] 0 a b > [2] a 0 c > [3] b c 0 > > matrix 2 > [1] [2] [3] > [1] 0 x y > [2] x 0 z > [3] y z 0 > > The matrix I want > [1] [2] [3] > [1] 0 a b > [2] x 0 c > [3] y z 0 > > Thanks, > > FZ. > > _______________________________________________ > R-SIG-Mac mailing list > R-SIG-Mac@stat.math.ethz.ch > https://stat.ethz.ch/mailman/listinfo/r-sig-mac > [[alternative HTML version deleted]] _______________________________________________ R-SIG-Mac mailing list R-SIG-Mac@stat.math.ethz.ch https://stat.ethz.ch/mailman/listinfo/r-sig-mac
