Abdulaziz Ghuloum <[EMAIL PROTECTED]> writes: > On Aug 25, 2007, at 8:41 AM, Keith Wright wrote: > >> On page 30, section 10, we have the example: >> >> (let () >> (define-syntax foo >> (lambda (e) >> (let ([+ -]) (+ 1 2)))) >> (define + 2) >> (foo)) >> >> The second argument of |define-syntax| should >> evaluate to a transformer (pg 31, 11.2.2). >> A tranformer is...a procedure that must... >> return a syntax object (lib pg 51, 12.3). >> >> The procedure in the example returns a number. > > A number is a datum and every datum is a syntax > object. Refer to r6rs-lib 12.2 for the definition > of "syntax-object" and the distinction between > a wrapped and an unwrapped one. > > The listed example is correct.
Whoops. Forgot about that. Will (un)fix. Thanks! -- Cheers =8-} Mike Friede, Völkerverständigung und überhaupt blabla _______________________________________________ r6rs-discuss mailing list [email protected] http://lists.r6rs.org/cgi-bin/mailman/listinfo/r6rs-discuss
