Mathematically, limit (expt x y), x->0, y->0 is undefined, in the same sense that limit (/ x y), x->0, y->0 is undefined.
Chongkai Abdulaziz Ghuloum wrote: > > On Aug 10, 2008, at 8:15 PM, Chongkai Zhu wrote: > >> I can't understand why (expt 0 0) should be 1. Would anyone explain? > > Because 1 is the identity of the multiplication operation. _______________________________________________ r6rs-discuss mailing list [email protected] http://lists.r6rs.org/cgi-bin/mailman/listinfo/r6rs-discuss
