I understand. However, not only that disregards type promotion but also is incoherent since (+ 0 0.0) evaluates to 0.0.

On 13-02-2011 16:17, Robby Findler wrote:
I believe one of the rules is that multiplying exact 0 by any number
gives you back exact 0.

Robby

2011/2/13 José Lopes<[email protected]>:
Shouldn't (* 0.0 0) evaluate to 0.0?

--
José António Branquinho de Oliveira Lopes
58612 - MEIC-A
[email protected]

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José António Branquinho de Oliveira Lopes
58612 - MEIC-A
[email protected]

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