I suppose that would work. Sam suggested on #racket that I include the name of the argument in the macro definition:
(define-syntax-rule (foo bar form ...) ((lambda (bar) form ...) "ARG")) Then you could say: (foo bar ; Do stuff with bar here... ) On Fri, Sep 16, 2011 at 1:12 PM, Matthias Felleisen <[email protected]>wrote: > > > Why not just store the arguments to lambda in some 'register' and ask for > them? > > > > > On Sep 16, 2011, at 4:09 PM, Daniel MacDougall wrote: > > > In this example it should return "ARG". > > > > On Fri, Sep 16, 2011 at 1:08 PM, Matthias Felleisen < > [email protected]> wrote: > > > > > > What should (foo bar) return? > > > > > > On Sep 16, 2011, at 3:46 PM, Daniel MacDougall wrote: > > > > > Is there any way to define a macro that expands out to a lambda, and > then access the arguments passed to that lambda from outside the macro in > the calling context? > > > Here's an example of what I mean: > > > > > > #lang racket > > > > > > (define-syntax-rule (foo form ...) > > > ((lambda (bar) form ...) "ARG")) > > > > > > (foo "Hello") ; => returns "Hello" > > > > > > (foo bar) ; => expand: unbound identifier in module in: bar > > > > > > > > > I'd like access to the "bar" argument on the last line. Is this > possible with Racket macros? > > > > > > Thanks, > > > Daniel > > > _________________________________________________ > > > For list-related administrative tasks: > > > http://lists.racket-lang.org/listinfo/users > > > > > >
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