;; equation3 : number -> boolean ;; to determine whether n is a solution for 2n^2 = 102 (define (equation3 n) (=~ (* 2 n n) 102 .001))
-- Matthias On Oct 22, 2013, at 8:40 AM, Bo Gus <foruman...@gmail.com> wrote: > equation 2 is 2n^2 = 102 so I implement like this: > > ;; equation3 : number -> boolean > ;; to determine whether n is a solution for 2n^2 = 102 > (define (equation3 n) > (= (* 2 n n) 102)) > > And my answer is the same as per the online answer. so great. > > But how can I check a valid answer. > > Eg if I do: > > (equation3 (sqrt 51)) > >false > > same using - square root 51. > > How can I fix this? Is the only way to do a range check? Eg have some sort > of tolerance - eg between 0.01 above and below answer? Any other ideas? > > ____________________ > Racket Users list: > http://lists.racket-lang.org/users ____________________ Racket Users list: http://lists.racket-lang.org/users
