All,
I am sure this question has been answered before, but I can't find it.
Suppose I want to call some function, either built-in or user-defined, n number
of times, and measure the total time it takes. Is there a more efficient or
elegant way
of doing this than passing the expression to a tail-recursive counting loop
such as the following?
(define (repeater sexpr count)
(sexpr)
(cond
[(> count 0) (repeater sexpr (- count 1)) ])
)
George Rudolph
Associate Professor of Computer Science
Department of Mathematics and Computer Science
225 Thompson Hall
The Citadel
171 Moultrie Street
Charleston, SC 29409
843.953.5032
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