Actually, ~a by itself might do what you want. (~a 1 2 3) ; => "123"
On Fri, Jul 3, 2015 at 4:18 PM, Stephen Chang <[email protected]> wrote: > I think the call to "values" is misplaced. > > Here's a functioning version of foo, and a perhaps more concise alternative: > > (define (foo . L) > (let ([bar (string-join (build-list (length L) (λ (x) "~a")) "")]) > (apply format bar L))) > > (define (my-foo . L) > (string-join (map ~a L) "")) > > On Fri, Jul 3, 2015 at 4:06 PM, mazert <[email protected]> wrote: >> Hello, >> >> To directly go to the essential : here is an example : >> >> (define (foo . L) >> (let ([bar (string-join (build-list (length L) (λ (x) "~a")) "")]) >> (format bar (apply values L)))) >> >> Globally, I want to use a function who has variable parameters within a >> function who has variable parameters too. >> >> It is possible ? >> Thanks in advance. >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Racket Users" group. >> To unsubscribe from this group and stop receiving emails from it, send an >> email to [email protected]. >> For more options, visit https://groups.google.com/d/optout. -- You received this message because you are subscribed to the Google Groups "Racket Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
