(regexp-match* #px"(AA.+?AA)" str)
regexp-match* matches multiple times through the string.
As with Perl and pcre in general, a trailing '?' makes quantifers
non-greedy.
On Sat, Nov 5, 2016 at 8:59 AM, <meino.cra...@gmx.de> wrote:
> Hi Jens,
>
> thanks for your reply! :)
>
> ...hmmm...I /think/ I understand the mechanism now...but
> if it is as it seems to be...I run into another problem.
>
> Suppose your have a long line of character with groups
> of certain chararcter and random caharcters in between.
>
> Something like this
> SHDKJSHKDAHSKJDHSKAABBBAAAKAJSHDOQWDASLDLAAAMEINOAAJASLAKJDL
> SJDLAAJENSAASJHDKASHDK
>
> The pattern here is AA<a word,no space>AA.
>
> The first idea, which came into my mind would be to match with
> something like
>
> (regex-match rx#"(AA[A-Z]+AA))
>
> (beside the fact, that I currently dont know, how to match non
> greedily): The guide says:
>
>
> > (regexp-match #rx"([a-z ]+;)*" "lather; rinse; repeat;")
>
> '("lather; rinse; repeat;" " repeat;")
>
> Here, the *-quantified subpattern matches three times, but it is the
> last submatch that is returned.
>
> So I would get back AAJENSAA and AAMEINOAA would be matched but not
> included in the list of matched strings.
>
> If the line is of unknown length as the count of "AA<word>AA" groups
> is, I would not know how to cope with this?
>
> Is there any other way to get back a list of all found matches instead
> of only he last one?
>
> Thank you very much in advance for any help!
> Cheers
> Meino
>
>
>
>
> Jens Axel Søgaard <jensaxelsoega...@gmail.com> [16-11-04 20:28]:
> > The first result string is the first matched string. The second result
> is what was matched by the sub expression in the parenthesis.
> >
> >
> > > Den 4. nov. 2016 kl. 20.04 skrev meino.cra...@gmx.de:
> > >
> > > Hi,
> > >
> > > Normally I would tend to think, that I am
> > > quite familiar with regex and their usage
> > > (background: UNIX?Linux, sed, vi/vim, Perl...)
> > >
> > > Then I played a little with regex-match...and
> > > I have to go to school again..,,
> > >
> > > From the Racket guide:
> > >> (regexp-match #rx"([a-z ]+;)*" "lather; rinse; repeat;")
> > > '("lather; rinse; repeat;" " repeat;")
> > >
> > > [a-z ]: matches one lowercase character of the range of a-z and the
> #\space
> > > + : the above one ore more times
> > > ; : followed by a ';'
> > > () : all the above grouped
> > > * : 0 or more times
> > > seems obvious..
> > >
> > > But the result is not (at least for me... ;)
> > > '("lather; rinse; repeat;" " repeat;")
> > >
> > > I understand "lather; rinse; repeat;" as match -
> > > it reflects the "greedy behaviour" of regex.
> > >
> > > But " repeat;" ???
> > >
> > > Why not "rinse; repeat;" then???
> > >
> > > I am buffled...<scratching my head>
> > >
> > > (help!)+
> > >
> > > :)
> > >
> > > (Thank you)+ (much)+ in advance!
> > > Cheers
> > > Meino
> > >
> > >
> > >
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