This is interesting. The `Any` type in Typed Racket includes values that may 
have higher-order "original" types. For example, it may have originally been a 
typed function (-> Fixnum Fixnum) or (-> String Boolean), such that if you call 
it without a contract guarding it, it should be an error. This is because `Any` 
is a super type of those types.

However, the value returned by `dynamic-require` is different from a normal 
`Any`. It will never be an unguarded "originally" typed value, so it should be 
safe to pass it to `cast` without adding a new guard. It might make sense to 
define a new type `UntypedAny` or maybe `GuardedAny`. There are two differences:
  (1) this type is *not* a super type of any other type that might involve 
higher-order values
  (2) it is safe to pass a value of this type into untyped code without an 
additional guard

Point (2) is what would allow `cast` to work, and point (1) is what would make 
that safe to do.

With this new `UntypedAny` type, dynamic-require could return the type 
`UntypedAny` instead of `Any`.

--------------------------------------------------

Why this would allow `cast` to work (and why `require/typed` is a good 
workaround for now)

The difference between `cast` and `require/typed` is this:
 - `require/typed` guards value going from Untyped -> Typed
 - `cast` guards values going from Typed -> Untyped -> Typed

The `cast` needs the extra Typed -> Untyped boundary to guard "originally" 
typed higher-order values, such as a (-> Fixnum Fixnum) function annotated as 
`Any`. However, `require/typed` takes its values from an untyped context to 
begin with, so it doesn't need to deal with that extra boundary.

The value returned by `dynamic-require` is never one of those typed 
higher-order values, and if the type system knows that through the `UntypedAny` 
type, the type system will know it is safe to make `cast` behave like 
`require/typed`.

It will know it is safe to pass it only through the Untyped -> Typed boundary.

Alex Knauth

> On Apr 16, 2018, at 10:01 AM, Matthias Felleisen <matth...@felleisen.org> 
> wrote:
> 
> 
> Have you considered organizing your program as follows: 
> 
> #lang racket
> 
> (module a racket
>   (provide f)
>   (define (f x) 10))
> 
> (module b racket
>   (provide g)
>   (define g (dynamic-require '(submod "foo.rkt" a) 'f)))
> 
> (module c typed/racket
>   (require/typed (submod ".." b) [g (-> Integer Integer)])
>   (g 20))
> 
> (require 'c)
> 
> That is, run the dynamic-require in an untyped module and then import it at 
> the desired type? 
> 
> 
> 
>> On Apr 16, 2018, at 5:22 AM, mailoo <dmichi...@mailoo.org 
>> <mailto:dmichi...@mailoo.org>> wrote:
>> 
>> 
>> Hello,
>> 
>> I'm new to racket, and even more with typed/racket.
>> 
>> I play a little with the "Any" type (due to 'dynamic-require' which return 
>> Any), and I'm not able to cast them back in a function.
>> 
>> I (over) simplify my question with this little program :
>> 
>> ```
>> (: p Any)
>> (define (p i) (displayln i))
>> 
>> ; Here I want to get back my function
>> (define proc (cast p (-> Integer Void)))
>> (proc 2)
>> 
>> ```
>> 
>> but I get this error when I try to execute the function :
>> 
>> ```
>> ; contract violation
>> ;   Attempted to use a higher-order value passed as `Any` in untyped code: 
>> #<procedure:p>
>> ;   in: Any
>> ;   contract from: typed-world
>> ;   blaming: cast
>> ;    (assuming the contract is correct)
>> ;   at: <pkgs>/racketFBP/test.rkt:13.13
>> ; Context:
>> ;  /home/denis/dev/racket/racketFBP/test.rkt:1:1 [running body]
>> ; [Due to errors, REPL is just module language, requires, and stub 
>> definitions]
>> ```
>> 
>> In reality, I get my function by `(dynamic-require path 'p)`, and I didn't 
>> find a typed version of this function...
>> 
>> Is there a way to go from Any to a function, or to replace my use of 
>> `dynamic-require`?
>> 
>> Thank you in advance,
>> Denis Michiels
>> 
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