Dear all,
I am learning call/cc in racket, so I wrote some experiment code:
#lang racket
(begin
(define saved-k #f)
(+ 1 (call/cc
(lambda (k) ; k is the captured continuation
(set! saved-k k)
0)))
(println 'hello)
(saved-k 100)
;; why 'hello not print more than once??
)
The execution result of this codeis:
1
hello
101
It does not meet my expectation, my expectation is :
1
hello
101
hello
101
....loop
About continuation, for example:
assume exp1 is:
(+ 1 (call/cc
(lambda (k) ; k is the captured continuation
(set! saved-k k)
0)))
exp2 is:
(println 'hello)
Whether exp2 is the continuation of exp1
Are these two expressions equivalent?
(begin
(exp1)
(exp2))
(exp1 (lambda (v)
(exp2 continuation-of-exp2)))
So exp2 is exp1's continuation?
It makes me confused.
Excuse me, this question may be stupid, forgive my ignorance...
Thanks.
Br,
serioadamo97
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