2012/8/4 ZulTan <zul_...@yahoo.com>

> Assalamu'alaikum warahmatullaahi wabarakaatuhu,
>

Wa'alaykumus salaam warahmatullahi wabarakaatuh,


> Problem 1:
> A boat travels 12 km upstream and back in 1 hour 45 minutes.
> If the speed of the current is 3 km/h throughout, find the speed of the
> boat in still water, giving your answer correct to 3 significant figures.
>

s = 12 km
t = 1.75 h

12 / (v - 3) + 12 / (v + 3) = 1.75
(12(v+3) + 12(v-3))/(v^2 - 9) = 1.75
12(v+3) + 12(v-3) - 1.75(v^2 - 9) = 0
12v + 36 + 12v - 36 - 1.75v^2 + 15.75 = 0
- 1,75v^2 + 24v + 15,75 = 0

v = 14.342 km/h


> Problem 2:
> A motorist makes a journey of 240 km from Singapore to Malacca to visit
> his in-law at an average speed of X km/h. Write down an expression for the
> number of hours taken for the journey.
>

t1 = 240/X hour


> On his return jouney from Malacca to Singapore, his average speed is
> reduced by 6 km/h due to heavy traffic at the causeway. Write down an
> expression for the time taken for the return journey.
>

t2 = 240/(X - 6) hour



>  If the return journey takes 20 minutes longer, from an equation in X and
> solve it to find the average speed for each journey, giving your answer
> corret to two decimal places.
>

t2 = t1 + 1/3 hour

240/(X - 6) = 240/X + 1/3
720X - 4320 + X^2 - 6X - 720X = 0
X^2 - 6X - 4320 = 0

X = 68.80

X1 = X = 68.80
X2 = X - 6 = 62.80

Nice to have argumentation of mathematical nature, instead of ad populum
and ad verecundiam ones. Thank you, Pak ZulTan.

-- 
Abu 'Abdirrahman, Ahmad Ridha bin Zainal Arifin bin Muhammad Hamim
(l. 1400 H/1980 M)

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