> (x-y) (x+y) = y(x-y)
Of course, you can't divide both sides by (x-y) because x-y=0 and you can't
divide by zero.
BUT, if TOLERANCE is set greater than or equal to 1, then 1=2 in RBase.
Regards,
Stephen Markson
ForenSys The Forensic Systems Group
www.ForensicSystemsGroup.com
416 482 2140
----- Original Message -----
From: "Bernard Lis" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Sunday, July 29, 2001 3:15 PM
Subject: Re: RBDos 6.5++ LASTKEY function seems faulty
> I can't resist this -- your while 2 > 1 reminded me that 2 is really
> equal to 1. Proof follows:
>
> x=1 y=1 therefore x = y
> multiplying both sides by x gives
> x(2) = xy that's read as x squared
> subtracting y(2) from both sides we get
> x(2) - y(2) = xy - y(2)
> factoring: difference of 2 squares and common factor
> (x-y) (x+y) = y(x-y)
> canceling x-y on both sides we get:
> x + y = y or
> 2 = 1
>
> Yours truly,
> Bernie Lis
