Hi

I don't think the reaction SMARTS does specify a change in the
charges. The N and O have to be charged in order to match the reactant
pattern but they won't be altered by the transformation. If you
specify that the product atoms are explicitly neutral I think you'll
get the result you want -
[#8-:2]-[#7+:1]=[O:3]>>[O+0:2]=[N+0:1]=[O:3]

Chris Earnshaw

On 9 October 2017 at 15:57, Chris Murphy <chris.mur...@schrodinger.com> wrote:
> Hi,
>
> I am using rdChemReactions to perform substructure transformations as
> defined by configurable reaction smarts. When I create the reaction and run
> a mol through it that I expect to be transformed by the indicated reaction
> smarts, I see that the bonds have been changed according to the smarts, but
> the charges are not changed.
>
> I am using the following smarts to define the transformation:
> [#8-:2]-[#7+:1]=[O:3]>>[O:2]=[N:1]=[O:3]
>
> The input molecule is as follows:
>
>   Mrv16c5 10061718252D
>
>   9  9  0  0  0  0            999 V2000
>    -0.5916   -0.0678    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
>    -1.3060   -0.4803    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
>    -1.3060   -1.3054    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
>    -0.5916   -1.7179    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
>     0.1229   -1.3054    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
>     0.1229   -0.4803    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
>    -0.5916    0.7572    0.0000 N   0  3  0  0  0  0  0  0  0  0  0  0
>    -1.3061    1.1697    0.0000 O   0  5  0  0  0  0  0  0  0  0  0  0
>     0.1229    1.1697    0.0000 O   0  0  0  0  0  0  0  0  0  0  0  0
>   1  2  2  0  0  0  0
>   2  3  1  0  0  0  0
>   3  4  2  0  0  0  0
>   4  5  1  0  0  0  0
>   5  6  2  0  0  0  0
>   6  1  1  0  0  0  0
>   1  7  1  0  0  0  0
>   7  8  1  0  0  0  0
>   7  9  2  0  0  0  0
> M  END
> $$$$
>
> and the output ends up being:
>
>      RDKit          2D
>
>   9  9  0  0  0  0  0  0  0  0999 V2000
>    -1.3061    1.1697    0.0000 O   0  0  0  0  0  0  0  0  0  0  0  0
>    -0.5916    0.7572    0.0000 N   0  0  0  0  0  0  0  0  0  0  0  0
>     0.1229    1.1697    0.0000 O   0  0  0  0  0  0  0  0  0  0  0  0
>    -0.5916   -0.0678    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
>    -1.3060   -0.4803    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
>     0.1229   -0.4803    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
>    -1.3060   -1.3054    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
>     0.1229   -1.3054    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
>    -0.5916   -1.7179    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
>   1  2  2  0
>   2  3  2  0
>   4  2  1  0
>   4  5  2  0
>   6  4  1  0
>   5  7  1  0
>   8  6  2  0
>   7  9  2  0
>   9  8  1  0
> M  CHG  2   1  -1   2   1
> M  END
>
> It seems the that NO bond is successfully converted to a double bond, but
> the charges have not been changed, even though the reaction smarts indicates
> that they N and O should be changed to neutral. Are there any glaring issues
> with using reactions to do transformations like this?
>
> Thanks!
>
> -Chris
>
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