Dear All,

I wonder if I can quickly sanity-check something(?).

I have noticed that symmetrical double bonds output with a bond stereo setting 
of "3" (cis or trans (either) double bond) in the standard molblock output.
Is this expected/intentional?  I would have expected a setting of "0" (use 
coords to determine cis or trans) for a non-stereo double bond.
(I am using 2020.09.1)

Here's a simple example:

m = Chem.MolFromSmiles('FC(F)=CC1=CC=CC=C1')
print(Chem.MolToMolBlock(m))


     RDKit          2D

10 10  0  0  0  0  0  0  0  0999 V2000
    5.2500   -1.2990    0.0000 F   0  0  0  0  0  0  0  0  0  0  0  0
    3.7500   -1.2990    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    3.0000   -2.5981    0.0000 F   0  0  0  0  0  0  0  0  0  0  0  0
    3.0000    0.0000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    1.5000    0.0000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    0.7500   -1.2990    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   -0.7500   -1.2990    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   -1.5000    0.0000    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
   -0.7500    1.2990    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
    0.7500    1.2990    0.0000 C   0  0  0  0  0  0  0  0  0  0  0  0
  1  2  1  0
  2  3  1  0
  2  4  2  3
  4  5  1  0
  5  6  2  0
  6  7  1  0
  7  8  2  0
  8  9  1  0
  9 10  2  0
10  5  1  0
M  END


This behaviour is maybe what I would expect if the bond was explicitly set 
using bond.SetStereo(Chem.BondStereo.STEREOANY), but in the absence of this I 
would expect the bond to default to STEREONONE, and I guess I would expect this 
to be bond stereo "0" in the output molblock.  What am I missing?

Kind regards

James
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