Bob-O and Todd,
In theory you're right, Bob-O. I find the program awkward to use,
given that it thinks in some weird (Danish?) way, that I don't use
often enough to remember how to navigate. But in this case my
bigger concern would be how to input data for a bunch of old used
Astropower 75s. Astropower's been gone for over ten years, I
think, and data isn't likely to show up on the backsheets. WINCaps
doesn't account for module degradation, either.
Todd, I might have a copy of a module spec sheet for the AP75 in
our files at the office. Not sure, as we never used any, but I
collected a lot of that old crap. Contact me off list on Monday if
you need me to look.
Allan
Allan Sindelar
al...@positiveenergysolar.com
NABCEP Certified Photovoltaic
Installer
NABCEP Certified Technical Sales Professional
New Mexico EE98J Journeyman Electrician
Founder and Chief Technology Officer
Positive Energy, Inc.
3209 Richards Lane (note new address)
Santa Fe, New Mexico 87507
505 424-1112
www.positiveenergysolar.com
On 5/31/2013 11:14 AM, Bob-O Schultze wrote:
Todd,
The easiest way to do this is to use the Grundfos pump sizing
software. Regrettably, it only runs on a PC. You can input the
specs of the module, the head and the GPD desired and it will
size the array for you. Once you know the # of modules in series
you can use the Imp and Vmp derated for temperature which will
get you in the right ballpark for sizing the conductors. Won't
be accurate, but close 'nuff.
Good Luck, bob-O
On May 30, 2013, at 3:29 PM, Todd Cory wrote:
this question is part 2 about the customer
with the used astropower 75 watt modules -
he has a grundfos 11sqf-2 already set by the well
driller. the input specifications for the cu200 pump
& controller are 30 to 300 vdc, 1400 watts, 8 amps.
this will initially be running array direct and i am
trying to figure out the wire loss from the modules to
the cu200 controller. to do that i need voltage and
current numbers. im assuming the higher the voltage the
lower the running current?
from the specs above: 1400 watts divided by 8 amps = 175
volts... so if i feed this with closer to 300 volts
would that mean the running current would drop to around
4.6 amps?
thanks for the help,
todd
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