IMO a much simpler treatment is "if the list is improper, use nfx"
without counting anything.
So in order for the "alternating symbol" rule to trigger:
1. The contents should be a proper list
2. The list should have an odd number of elements
3. The even elements (counting the first element as odd) should be
the same symbol, as compared by eq? and must return true when applied
to the symbol? predicate
otherwise, (cons 'nfx <>) on the list.
On Fri, Aug 17, 2012 at 9:38 PM, David A. Wheeler <dwhee...@dwheeler.com> wrote:
> I said:
>> I think that if you have an improper list, the last ("improper") item should
>> count as length 1.
>
> Hmm, my modified implementation isn't exactly the same as my proposed
> description, and I'm not sure which one is best.
>
> The modified implementation translates:
> {a + . z}
> into:
> (nfx a + . z)
>
> If I was serious about "improper = length 1" then it should be "(+ a .
> z)"instead.
>
> This is all an edge case. The most *important* thing is to avoid crashing
> and to have a concise universal definition. That said, I'd like even the
> edge cases to be soundly justified and "obviously right". Thoughts?
>
> --- David A. Wheeler
>
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