It seems that a totally unrelated issue was throwing my index
reference out, not the behaviour of the arrays as I thought.
Without going into too much detail, it stemmed form the fact that a
page panel I was dynamically adding and removing pages from had an
initial pagecount of 1 instead of 0.
Sorry to confuse everyone.
- Tom
On 11/01/2007, at 10:08 AM, Terry Ford wrote:
On Jan 10, 2007, at 2:53 PM, William Squires wrote:
On Jan 10, 2007, at 7:10 AM, Tom Benson wrote:
I just need a single dimensional array that stays in sequential
index order whenever I remove an element.
I know I could rebuild an array once I remove an entry, but the
arrays I'm dealing with could get rather large (10,000 + elements).
If there is a better framework solution for this, then someone
tell me, because I can't find one.....
- Tom
You'd have to write a wrapper class, and handle the 'Remove's
yourself. Or just remove the last element of the array. i.e. if -
in your example - you remove element three, then rearrange the
contents so that elements 3 and 4 contain 'three' and 'four'
again, then you get the same thing as if you had just removed the
element at the end (namely, 5, in your case) which seems like a
lot simpler solution (IIRC, the Pop method of an array will do
this for you.)
Besides the fact that there already is a built-in method that does
exactly what he wants, to do a similar method in a multi-
dimensional array, one would start at the group of elements to be
removed and replace all elements with those with an index just
above it. One would then repeat this for each subsequent group of
elements until the Ubound of the array is reached. Actually, this
is what array.remove(x) does but it only does it for a one-
dimensional array.
I believe there is a feature request to allow this in multi-
dimensional arrays.
Terry
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