At 07:56 PM 2/5/2007, you wrote:
What about just using a string? and midB?
Again, I wasn't looking for a workaround - I want to use Byte Arrays AS a workaround for something else.
I have lots of VB code I want to simply paste into RB, and that uses lots of buffers, ALWAYS using byte arrays. In VB, byte arrays are very fast used with memcpy-type functions to move things around and into other byte arrays.
It's simply the syntax and the pain to hand-edit lots of code to switch them to memoryblocks that I'm trying to avoid. Right now I have wrapper functions that do the trick of blasting bytes, but they use loops and it's likely much slower then a pointer/copy fucntion that I'm checking in List-Land (soon to be Forum-Land, sniff) to see if there's a pointer function to the inhouse RB arrays.
> >Actualy sounds to me like you might want to consider using a > >memoryblock instead. > > That's sort of the backdoor. I'm trying to use lots of VB code pasted > to RB, which uses byte arrays, and trying to avoid changing them to > memory blocks. I'm completely used to using Byte Arrays as buffers. > > VB has a way of obtaining the pointer from a byte array; in fact, you > just pass the first (or whatever) element to RtlMoveMemory in the C > runtime, the Declare in VB interprets that as a pointer. Pointers in > VB can be used, you just can't do anything directly to them. You > receive a pointer to pass it. I'm just looking for it in the first place. > > So presently there is no way of getting a pointer to an element in a > Byte Array in RB? > > >Also a simple benchmark might give you the answer. > > True, but I already know the outcome (could be wrong though). > > >I'd be interested to know if memoryblocks and memcpy beats simply > >looping round the byte array in the normal fashion. > > I'll try, at least. > > >You cannot get pointers to an RB array. They are reference based only. > > RB knows them, so somehow they could be exposed? > > >If you want to play with pointers you have to be dealing with > memoryblocks > >and/or ptrs derived from Declares. > > See above.
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