Hi Ladislav, > parse ['a] [1 1 'a] ; == false
It seems to me there that this is a consequence of aggressive evaluation: >> parse [a] [1 1 'a] ;== true parse try to check a word and not a lit-word and we can't use a get-word in a parse block: >> b: to-lit-word 'a ;== 'a >> type? b ;== word! >> type? :b ;== lit-word! Now this check the word! a not the lit-word! 'a parse ['a] [1 1 b];== false this check the get-word :b not the value of b parse ['a] [1 1 :b];== false while in this case :b is used as a parse command parse ['a] [:b];== false Also 2.5 has this side effect in spite of the less aggressive evaluation. --- Ciao Romano -- To unsubscribe from this list, please send an email to [EMAIL PROTECTED] with "unsubscribe" in the subject, without the quotes.
