> Hi Gregg,
> 
> >     ; There has *got* to be a better way than this!
> >     bxor: func [set1 [bitset!] set2 [bitset!] /local b1 b2] [
> >         (head system/words/clear at to binary! set1 add 1 divide length?
> > set1 8)
> >         xor
> >         (head system/words/clear at to binary! set2 add 1 divide length?
> > set2 8)
> >     ]
> 
> Can be?
> 
> exclude union set1 set2 intersect set1 set2
> 

Better?

 difference set1 set2

---
Ciao
Romano


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