Ladislav,

Your 2 cents worths more than my  50 cents
Thanks.

Emeka

2010/8/24 Ladislav Mecir <[email protected]>

>
>  Dne 23.8.2010 19:26, Arie van Wingerden napsal(a):
> > Indeed that is the way it works.
> > In Lisp a list (when unquoted!) is always evaluated.
> > In Rebol evaluation is not standard, but must be triggered by a calling
> > function (outside the block). And indeed also, when a block is being
> > evaluated functions within the block will be recognized and evaluated
> also.
> >
> > 2010/8/23 Emeka<[email protected]>
> >
> >> Hello All,
> >>
> >> This where I got my conclusion.
> >>
> >> I mentioned before that blocks are a container type. An ordered sequence
> of
> >> values. Actually they are an ordered sequence of un-evaluated values.
> What
> >> that means is that when a block itself is evaluated the values it
> contains
> >> are not evaluated. The values a block contains are evaluated when a
> >> function
> >> is applied to the block
> >>
> >>
> >>
> http://www.codeconscious.com/rebol/articles/rebol-concepts.html#Firsttrapforbeginners
> >>
> >>
> >> Is the last statement correct?
> >>
> >>
> >> Emeka
> >>
> ...the rest snipped...
>
> The funny thing about the discussion above is, that although the
> contributors look like being in mutual agreement, their statements
> actually are not.
>
> Let me try to add my two cents in hope I do not add more confusion to
> the subject.
>
> First, let's examine the expression:
>
>     do [
>         ; this is the "outer block"
>         length? [
>             ; this is the "inner block"
>             1
>         ]
>     ]
>
> Such an expression is quite frequently referred to as: "The (outer)
> block in the above expression is evaluated by the DO function."
>
> When describing, how the DO function interprets the (outer) block, the
> documentation sources say, that "The values and words of the block are
> computed from left to right." Notice, that the word used is not
> "evaluated", but "computed". That is a necessary terminological
> distinction, since the inner block is not "evaluated" in the same way as
> the outer block is, it is just "computed", which actually means, that
> the inner block is supplied "as is" to the LENGTH? function. In this
> case, the LENGTH? function does not do any further "evaluation" of the
> inner block, it just yields the length of the inner block as its result.
>
> Hope, that this "terminological detour" was of some help.
>
> -Ladislav
>
> P.S. the usage of the "un-evaluated values" notion I see as quite
> unfortunate, since it looks more confusing than explaining.
>
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