> How do you sort a block of blocks on an element other than the first?
>
> For example:
>
> db: [
> ["bob" "Smith" "12"]
> ["dan" "murphy" "25"]
> ["mike" "Coogan" "6"]
> ]
>
> How do I sort by last name or by age
>> DB: ["Bob" "Smith" 12 "Dan" "Murphy" 25 "Mike" "Coogan" 6]
== ["Bob" "Smith" 12 "Dan" "Murphy" 25 "Mike" "Coogan" 6]
>> sort/skip/compare DB 3 2
== ["Mike" "Coogan" 6 "Dan" "Murphy" 25 "Bob" "Smith" 12]
>> sort/skip/compare DB 3 3
== ["Mike" "Coogan" 6 "Bob" "Smith" 12 "Dan" "Murphy" 25]
>> sort/skip/compare/reverse DB 3 3
== ["Dan" "Murphy" 25 "Bob" "Smith" 12 "Mike" "Coogan" 6]
>> help sort
USAGE:
SORT series /case /skip size /compare comparator /part length /all
/reverse
DESCRIPTION:
Sorts a series.
SORT is an action value.
ARGUMENTS:
series -- (Type: series port)
REFINEMENTS:
/case -- Case sensitive sort.
/skip -- Treat the series as records of fixed size.
size -- Size of each record. (Type: integer)
/compare -- Comparator offset, block or function.
comparator -- (Type: integer block function)
/part -- Sort only part of a series.
length -- Length of series to sort. (Type: integer)
/all -- Compare all fields
/reverse -- Reverse sort order
I hope that helps.
AJ Martin
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