I am a happy man. Thank you. And, I don't know how I missed that. Thanks again!
Jeff M. On 3/8/06, Tom Conlin <[EMAIL PROTECTED]> wrote: > > > Hi Jeff > > ? is also your friend. > > >> ? compose > USAGE: > COMPOSE value /deep /only > > DESCRIPTION: > Evaluates a block of expressions, only evaluating parens, and > returns a block > . > COMPOSE is a native value. > > ARGUMENTS: > value -- Block to compose (Type: any) > > REFINEMENTS: > /deep -- Compose nested blocks > /only -- Inserts a block value as a block > >> list: [a b c] > == [a b c] > >> compose/only [ 1 2 (list) 3] > == [1 2 [a b c] 3] > >> > > Jeff Massung wrote: > > Another question, folks (I'll be full of them for a bit). And, I > appreciate > > the quick answers I've been getting from everyone :-) > > > > How do I compose a list in a list? For example: > > > >>> list: [a b c] > > == [a b c] > > > >>> compose [ 1 (list) ] > > == [1 a b c] > > > > So, I would actually like it to be: [1 [a b c]]. Now, I can force this > by > > doing something like: > > > >>> list: [ [a b c] ] > >>> compose [ 1 (list) ] > > == [1 [a b c]] > > > > But this not only sure feels like voodoo-hackery, but just wrong. I'm > sorry > > if this is a trivial question and the answer is in the REBOL dictionary, > but > > looking through all the series functions, compose was the closest I got > to > > what I was looking for. > > > > Jeff M. > > > > -- > > [EMAIL PROTECTED] > > > > -- > ... nice weather eh [EMAIL PROTECTED] > > -- > To unsubscribe from the list, just send an email to > lists at rebol.com with unsubscribe as the subject. > > -- [EMAIL PROTECTED] -- To unsubscribe from the list, just send an email to lists at rebol.com with unsubscribe as the subject.
