On Tue, Feb 06, 2001 at 12:06:09AM +0800, Andrew So Hing-pong
<[EMAIL PROTECTED]> wrote:
| I would like to ask a question about regular expression & patten
| matching on the script writting.
|
| test.sh
| ...
| if [ $1 != "v[0-9][0-9].[0-9][0-9].[0-9][0-9]" ] ; then
| echo "Version must be vXX.XX.XX where X be a digit"
| else
| echo "Version -> [$1]"
| fi
|
| I want to ensure the $1 must v00.00.00 (an example), but the result
|
| #./test.sh v00.01.01
| Version must be vXX.XX.XX where X be a digit
|
| #./test.sh v[0-9][0-9].[0-9][0-9].[0-9][0-9]
| Version -> [v[0-9][0-9].[0-9][0-9].[0-9][0-9]]
This is because you're doing a string comparison, not a pattern match.
!= tests two strings for equality.
Before going further, just some notation: shell patterns (aka "globs")
are _not_ regular expressions, which has a different syntax. Ed,
vi/vim/nvi, emacs, perl, sek,awk et al use regular expressions. The
shell uses globs, which are much better notation when you're talking
about filenames.
To do your pattern match you want a case statement:
case "$1" in
v[0-9][0-9].[0-9][0-9].[0-9][0-9])
echo "Version -> [$1]"
;;
*) echo "Version must be vXX.XX.XX where X be a digit"
;;
esac
Cheers,
--
Cameron Simpson, DoD#743 [EMAIL PROTECTED] http://www.zip.com.au/~cs/
I recently saw a crash where a yokel in a lwb Landrover had pulled
out of a junction on a fast road in front of a speeding Volvo (one of teh big
estate cars). The volvo had t-boned it amidshipps at about 60mph The landrover
was badly dented. Need a couple of hours with a hammer to straighten the
panels. The Volvo was urecognisable from the turret forewards.
Brakes? Who cares?
- Andy Woodward, <[EMAIL PROTECTED]>
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