Jim.
Thanks for your help.
All this is to try another thing.
I'm beginning with this and I don´t know how get help.
My true problem is the next :
I've got 3 lans:
Lan A: 192.168.200.0 = all my clients computers are coneccted.
Lan B: 192.168.2.0 = there are 3 hosts where the clients A must be
access.
Lan C: 192.168.3.0 = where is connected the router
Linux:
Eth0: 192.168.200.100
Eth1: 192.168.2.100
Eth2: 192.168.3.100
Router : 192.168.3.17
LINUX has 3 ethernets so I can separate traffic and after set filters.
-------Lan A -- LINUX -- Lan C ==Internet
| |
| Lan B
All | |
Hosts hostCA hostCB
I want to use the linux red hat 7.3 to access internet lan C and access
another lanB from LAN A.
How Could mount this strategy ?
Is It must be very complicated ?
-----Mensaje original-----
De: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
En nombre de Jim Cunning
Enviado el: miércoles, 10 de julio de 2002 19:03
Para: [EMAIL PROTECTED]
Asunto: Re: RV: Routing
On Wed, 10 Jul 2002, Ximo Llacer wrote:
> I have 2 if :
>
> eth0=192.168.200.11
> eth1=192.168.2.189
>
> I have ip_forward = yes in /etc/networks.
>
> My route table is:
>
> Kernel IP routing table
> Destination Gateway Genmask Flags Metric Ref
Use Iface
> Lan A
> 192.168.2.0 192.168.2.189 255.255.255.0 UG 0 0
0 eth1
> 192.168.2.0 0.0.0.0 255.255.255.0 U 0 0
0 eth1
> Lan B
> 192.168.200.0 192.168.200.11 255.255.255.0 UG 0 0
0 eth0
> 192.168.200.0 0.0.0.0 255.255.255.0 U 0 0
0 eth0
>
> 127.0.0.0 0.0.0.0 255.0.0.0 U 0 0
0 lo
> Router
> 0.0.0.0 192.168.200.17 0.0.0.0 UG 0 0
0 eth0
>
>
> Host A = 192.168.2.100 GW=192.168.2.189
> Host B = 192.168.200.100 GW=192.168.200.11
>
> I can't to access to internet from Host A but Host B yes.
>
> Is correct this route table ?
>
> Can be that the linux 7.3 is protected anyway ?
>
> When I filter with iptraf it shows unreachable port.
When you say "I have 2 if" and list the addresses eth0=192.168.200.11
and
eth1=192.168.2.189, this must be another host (C?) that you are
intending
to use as an internal router to the internet router at 192.168.200.17.
Right?
I see two problems with the information you supplied. 1) Delete the
following lines from your route table--they are unnecessary, and might
actually be your main problem:
192.168.2.0 192.168.2.189 255.255.255.0 UG 0 0 0
eth1
192.168.200.0 192.168.200.11 255.255.255.0 UG 0 0 0
eth0
2) The (apparently default) gateway of 192.168.200.11 for host B means
that B must send to router C, which then must resend _on the same LAN_
to
192.168.200.17. This makes C a one-armed router, unnecessarily routing
packets that could go directly to the correct router. The default
gateway
for host B should be 192.168.200.17.
A more consistent configuration for hosts A and B, would be something
like
this:
Host A (192.168.2.100):
192.168.200.0 gw 192.168.2.189 (network route through host C)
0.0.0.0 gw 192.168.200.17 (default route to internet router)
Host B (192.168.200.100):
192.168.2.0 gw 192.168.200.11 (network route through host C)
0.0.0.0 gw 192.168.200.17 (default route to internet router)
For the return path, the internet router must have a network route:
192.168.2.0 gw 192.168.200.11 (through host C)
Jim Cunning
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