Robert P. J. Day,
On Saturday July 27, 2002 05:17, you said something about:
> On Sat, 27 Jul 2002, Anthony E. Greene wrote:
> > -----BEGIN PGP SIGNED MESSAGE-----
> > Hash: SHA1
> >
> > On 26-Jul-2002/05:50 -0400, "Robert P. J. Day" <[EMAIL PROTECTED]>
wrote:
> > >while i'm thinking about it, is there a way to get both
> > >the real and effective user names/UIDs? in case someone
> > >has "su"ed to root, is there a way to see the original
> > >login name?
> >
> > man id
>
> except, under limbo, "id -r" prints:
>
> id: cannot print only names or real IDs in default format (????)
>
> what's up with that?
It does the same on my 7.2 system. But probably because of this...
-r, --real print the real ID instead of effective ID, for -ugG
...so you have to tell it if this is for a user, group or groups.
An "id -ur" works fine for me. However, this only fixes the syntax
requirements for id. It seems id is broken. It never seems to identify the
real vs. the effective ids. I don't know if this is in id, su or bash though.
But to answer your original question...
You could use the "logname" command to do a comparison like so...
#!/bin/bash
# I did not test this (or even try) for portability.
ID=`id -un`
LOGINN=`logname`
if [ "$ID" == "$LOGINN" ] ; then
echo "Usernames Match : OK"
fi
exit 0
--
Brian Ashe CTO
Dee-Web Software Services, LLC. [EMAIL PROTECTED]
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