On Mon, 4 Nov 2002, Chad Skinner wrote:
> Is there a way in a bash script to trim the spaces from the front and end of
> a variable
>
> I have a script that contains the following variable definition
>
>
> BLOCKED_SERVICES="tcp,111,Sun RPC;\
> udp,111,Sun RPC;\
> tcp,443,Microsoft DS;\
> udp,443,Microsoft DS"
>
> I am wondering what the simplest method of extracting each of the three
> elements from each line of the variable. In otherwords, each line is a
> PROTOCOL, PORT_RANGE, and DESCRIPTION. I have tried a for loop in bash
> similar to the following.
>
> IFS=";"
>
> for SERVICE in $BLOCKED_SERVICES
> do
> # SEPARATE SERVICE VARIABLES
> PROTOCOL=`echo $SERVICE | $CUT -f1 -d","`
> PORT=`echo $SERVICE | $CUT -f2 -d","`
> MESSAGE=`echo $SERVICE | $CUT -f3 -d","`
>
> The problem is that this gives the protocol with the leading spaces and I
> need to get rid of them. Does anyone know how to do this or have a better
> solution.
>
How about like this?
while read PROTOCOL PORT MESSAGE
do
echo $PROTOCOL $PORT $MESSAGE
done <<-Eod
tcp 111 Sun RPC
udp 111 Sun RPC
tcp 443 Microsoft DS
udp 443 Microsoft DS
Eod
--
John Darrah (u05192) | Dept: N/C Programming
Giddens Industries | Ph: (425) 353-0405 #133
PO box 3190 | Ph: (206) 767-4212 #133
Everett WA 98203 | Fx: (206) 764-9639
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