לעדכן את הנתונים ולהריץ

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dox =4e-6; % [cm]
Na=4e15; % [cm^-3]
ni=1.4e10; % [cm^-3]
Vfb=0; % [V]
W=10e-4; % [cm]
L=10e-4; % [cm]
Mu=600; % [cm^2/V*sec]
epsox=3.9;
k=1.38e-23; % [J/K]
T=300; % [K]
eps0=8.85e-14;
epssi=11.85;
q=1.6e-19; % [C]


% 1

C=epsox*eps0*W*L/dox


phiF=k*T*log(Na/ni);
Xd=sqrt((4*epssi*eps0*phiF/q)/(q*Na));
Qdepmax=-q*Na*Xd;
Vt = Vfb-Qdepmax/(epsox*eps0/dox)+2*phiF/q

% 2

Cnew=epsox*eps0*W*L/(dox/2)
Vtnew = Vfb-Qdepmax/(epsox*eps0/(dox/2))+2*phiF/q

% 3

Vtt = 1;
Vgs=2;
KK=(epsox*eps0/dox)*Mu*W/L;
Vds=0; Ids1= KK*((Vgs-Vtt)*Vds-Vds^2/2)
Vds=.5; Ids2= KK*((Vgs-Vtt)*Vds-Vds^2/2)
Vds=1; Ids3= KK*((Vgs-Vtt)*Vds-Vds^2/2)
Vds=2; Ids4= Ids3

% 4

Ids=5e-6;
syms Vds;
s=solve(KK*((Vgs-Vtt)*Vds-Vds^2/2)-Ids,Vds);
max(double(s))

% 5

Ids=190e-6;
syms Vgs;
s=solve(KK/2*(Vgs-Vtt)^2-Ids,Vgs);
max(double(s))

% 6

% Sirtut Alef

% 7 

% answer 4 - Inversion charge near the drain is zeroed

% 8

% answer 3- mimtah ahori

% 9 

% answer 3 - Increases dep area between the drain and the bulk


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