This reminds me: http://combichem.blogspot.dk/2013/08/you-know-what-really-grinds-my-gears-in.html
2014-05-05 17:52 GMT+02:00 Edward d'Auvergne <[email protected]>: > Hi, > > This is an important difference. In the first case (back_calc[i] = > Minty[i]), what is happening is that your are copying the data into a > pre-existing structure. In the second case (back_calc = Minty), the > existing back_calc structure will be overwritten. Therefore the > back_calc structure in the calling code will be modified in the first > case but not the second. Here is some demo code: > > def mod1(x): > x[0] = 1 > > def mod2(x): > x = [3, 2] > > x = [0, 2] > print(x) > mod1(x) > print(x) > mod2(x) > print(x) > > I don't know of a way around this. > > Regards, > > Edward > > > On 5 May 2014 17:42, Troels Emtekær Linnet <[email protected]> wrote: >> Hi Edward. >> >> In the library function of b14.py, i am looping over >> the dispersion points to put in the data. >> >> for i in range(num_points): >> >> # The full formula. >> back_calc[i] = Minty[i] >> >> Why can I not just set: >> back_calc = Minty >> >> _______________________________________________ >> relax (http://www.nmr-relax.com) >> >> This is the relax-devel mailing list >> [email protected] >> >> To unsubscribe from this list, get a password >> reminder, or change your subscription options, >> visit the list information page at >> https://mail.gna.org/listinfo/relax-devel _______________________________________________ relax (http://www.nmr-relax.com) This is the relax-devel mailing list [email protected] To unsubscribe from this list, get a password reminder, or change your subscription options, visit the list information page at https://mail.gna.org/listinfo/relax-devel
