Github user NarineK commented on a diff in the pull request:
https://github.com/apache/spark/pull/8920#discussion_r40622879
--- Diff: R/pkg/R/DataFrame.R ---
@@ -1848,3 +1848,67 @@ setMethod("crosstab",
sct <- callJMethod(statFunctions, "crosstab", col1, col2)
collect(dataFrame(sct))
})
+
+#' Sort
+#'
+#' Sort a DataFrame by the specified column(s).
+#'
+#' @param x A DataFrame to be sorted.
+#' @param by A character column indicating the field to sort on
+#' @param decreasing Orderings for each sorting column
+#' @param ... Additional sorting fields
+#' @return A DataFrame where elements are sorted by input sorting columns.
+#' @rdname sort
+#' @name sort
+#' @aliases orderby
+#' @export
+#' @examples
+#'\dontrun{
+#' sc <- sparkR.init()
+#' sqlContext <- sparkRSQL.init(sc)
+#' path <- "path/to/file.json"
+#' df <- jsonFile(sqlContext, path)
+#' sort(df, TRUE, "col1","col2")
+#' sort(df, decreasing=TRUE, "col1")
+#' sort(df, decreasing=c(TRUE,FALSE), "col1","col2")
+#' }
+setMethod("sort",
+ signature(x = "DataFrame"),
+ function(x, decreasing=FALSE, col, ...) {
--- End diff --
Hi Felix,
we can of course, the only thing is, that I need to embrace df$age with a
sorting order and right now I'm doing it with string concatenation. I can try
to get the string columns name of df$age. That would be one option.
I'm not sure how I could concatenate the order to column object nicely. It
might make the code look ugly.
I could have
loop:
if (order == "asc") { asc(col) } else {desc(col)}
but this is not nice.
Let me know what do you think .
Thanks,
Narine
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