Github user NarineK commented on a diff in the pull request: https://github.com/apache/spark/pull/8920#discussion_r40622879 --- Diff: R/pkg/R/DataFrame.R --- @@ -1848,3 +1848,67 @@ setMethod("crosstab", sct <- callJMethod(statFunctions, "crosstab", col1, col2) collect(dataFrame(sct)) }) + +#' Sort +#' +#' Sort a DataFrame by the specified column(s). +#' +#' @param x A DataFrame to be sorted. +#' @param by A character column indicating the field to sort on +#' @param decreasing Orderings for each sorting column +#' @param ... Additional sorting fields +#' @return A DataFrame where elements are sorted by input sorting columns. +#' @rdname sort +#' @name sort +#' @aliases orderby +#' @export +#' @examples +#'\dontrun{ +#' sc <- sparkR.init() +#' sqlContext <- sparkRSQL.init(sc) +#' path <- "path/to/file.json" +#' df <- jsonFile(sqlContext, path) +#' sort(df, TRUE, "col1","col2") +#' sort(df, decreasing=TRUE, "col1") +#' sort(df, decreasing=c(TRUE,FALSE), "col1","col2") +#' } +setMethod("sort", + signature(x = "DataFrame"), + function(x, decreasing=FALSE, col, ...) { --- End diff -- Hi Felix, we can of course, the only thing is, that I need to embrace df$age with a sorting order and right now I'm doing it with string concatenation. I can try to get the string columns name of df$age. That would be one option. I'm not sure how I could concatenate the order to column object nicely. It might make the code look ugly. I could have loop: if (order == "asc") { asc(col) } else {desc(col)} but this is not nice. Let me know what do you think . Thanks, Narine
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