Github user jodersky commented on a diff in the pull request: https://github.com/apache/spark/pull/15398#discussion_r82849408 --- Diff: sql/catalyst/src/main/scala/org/apache/spark/sql/catalyst/util/StringUtils.scala --- @@ -25,26 +25,25 @@ object StringUtils { // replace the _ with .{1} exactly match 1 time of any character // replace the % with .*, match 0 or more times with any character - def escapeLikeRegex(v: String): String = { - if (!v.isEmpty) { - "(?s)" + (' ' +: v.init).zip(v).flatMap { - case (prev, '\\') => "" - case ('\\', c) => - c match { - case '_' => "_" - case '%' => "%" - case _ => Pattern.quote("\\" + c) - } - case (prev, c) => - c match { - case '_' => "." - case '%' => ".*" - case _ => Pattern.quote(Character.toString(c)) - } - }.mkString - } else { - v + def escapeLikeRegex(str: String): String = { + val builder = new StringBuilder() + var escaping = false + for (next <- str) { + if (escaping) { + builder ++= Pattern.quote(Character.toString(next)) --- End diff -- Every character after a backslash is quoted, so `\\a` becomes `\Q\\E\Qa\E`. Is this not the intended behaviour?
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