Github user jodersky commented on a diff in the pull request:
https://github.com/apache/spark/pull/15398#discussion_r82849408
--- Diff:
sql/catalyst/src/main/scala/org/apache/spark/sql/catalyst/util/StringUtils.scala
---
@@ -25,26 +25,25 @@ object StringUtils {
// replace the _ with .{1} exactly match 1 time of any character
// replace the % with .*, match 0 or more times with any character
- def escapeLikeRegex(v: String): String = {
- if (!v.isEmpty) {
- "(?s)" + (' ' +: v.init).zip(v).flatMap {
- case (prev, '\\') => ""
- case ('\\', c) =>
- c match {
- case '_' => "_"
- case '%' => "%"
- case _ => Pattern.quote("\\" + c)
- }
- case (prev, c) =>
- c match {
- case '_' => "."
- case '%' => ".*"
- case _ => Pattern.quote(Character.toString(c))
- }
- }.mkString
- } else {
- v
+ def escapeLikeRegex(str: String): String = {
+ val builder = new StringBuilder()
+ var escaping = false
+ for (next <- str) {
+ if (escaping) {
+ builder ++= Pattern.quote(Character.toString(next))
--- End diff --
Every character after a backslash is quoted, so `\\a` becomes `\Q\\E\Qa\E`.
Is this not the intended behaviour?
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