Github user aokolnychyi commented on a diff in the pull request:

    https://github.com/apache/spark/pull/16329#discussion_r93606051
  
    --- Diff: 
examples/src/main/scala/org/apache/spark/examples/sql/UserDefinedTypedAggregation.scala
 ---
    @@ -0,0 +1,87 @@
    +/*
    + * Licensed to the Apache Software Foundation (ASF) under one or more
    + * contributor license agreements.  See the NOTICE file distributed with
    + * this work for additional information regarding copyright ownership.
    + * The ASF licenses this file to You under the Apache License, Version 2.0
    + * (the "License"); you may not use this file except in compliance with
    + * the License.  You may obtain a copy of the License at
    + *
    + *    http://www.apache.org/licenses/LICENSE-2.0
    + *
    + * Unless required by applicable law or agreed to in writing, software
    + * distributed under the License is distributed on an "AS IS" BASIS,
    + * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
    + * See the License for the specific language governing permissions and
    + * limitations under the License.
    + */
    +package org.apache.spark.examples.sql
    +
    +// $example on:typed_custom_aggregation$
    +import org.apache.spark.sql.expressions.Aggregator
    +import org.apache.spark.sql.Encoder
    +import org.apache.spark.sql.Encoders
    +import org.apache.spark.sql.SparkSession
    +// $example off:typed_custom_aggregation$
    +
    +object UserDefinedTypedAggregation {
    +
    +  // $example on:typed_custom_aggregation$
    +  case class Employee(name: String, salary: Long)
    +  case class Average(var sum: Long, var count: Long)
    +
    +  object MyAverage extends Aggregator[Employee, Average, Double] {
    +    // A zero value for this aggregation. Should satisfy the property that 
any b + zero = b
    +    def zero: Average = Average(0L, 0L)
    +    // Combine two values to produce a new value. For performance, the 
function may modify `buffer`
    +    // and return it instead of constructing a new object
    +    def reduce(buffer: Average, employee: Employee): Average = {
    +      buffer.sum += employee.salary
    +      buffer.count += 1
    +      buffer
    +    }
    +    // Merge two intermediate values
    +    def merge(b1: Average, b2: Average): Average = Average(b1.sum + 
b2.sum, b1.count + b2.count)
    --- End diff --
    
    @michalsenkyr It is not required to create a new object in the `merge` 
method. One can modify the vars and return the existing object just like in the 
`reduce` method.  However, it is less critical here since this method will be 
called on pre-aggregated data and not for every element. On the one hand, I can 
apply here the same approach as in the `reduce` method to make the example 
consistent. On the other hand, the current code shows that it is not mandatory 
to modify vars. Probably, a comment might help. I am not sure which approach is 
better. Therefore, I am open to suggestions.


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