HyukjinKwon commented on a change in pull request #25360: 
[SPARK-28280][PYTHON][SQL][TESTS][FOLLOW-UP] Add UDF cases into group by clause 
in 'udf-group-by.sql'
URL: https://github.com/apache/spark/pull/25360#discussion_r312779019
 
 

 ##########
 File path: sql/core/src/test/resources/sql-tests/inputs/udf/udf-group-by.sql
 ##########
 @@ -20,29 +20,25 @@ SELECT 'foo', COUNT(udf(a)) FROM testData GROUP BY 1;
 SELECT 'foo' FROM testData WHERE a = 0 GROUP BY udf(1);
 
 -- Aggregate grouped by literals (hash aggregate).
-SELECT 'foo', udf(APPROX_COUNT_DISTINCT(udf(a))) FROM testData WHERE a = 0 
GROUP BY 1;
+SELECT 'foo', udf(APPROX_COUNT_DISTINCT(udf(a))) FROM testData WHERE a = 0 
GROUP BY udf(1);
 
 -- Aggregate grouped by literals (sort aggregate).
-SELECT 'foo', MAX(STRUCT(udf(a))) FROM testData WHERE a = 0 GROUP BY 1;
+SELECT 'foo', MAX(STRUCT(udf(a))) FROM testData WHERE a = 0 GROUP BY udf(1);
 
 -- Aggregate with complex GroupBy expressions.
 SELECT udf(a + b), udf(COUNT(b)) FROM testData GROUP BY a + b;
 SELECT udf(a + 2), udf(COUNT(b)) FROM testData GROUP BY a + 1;
-
--- [SPARK-28445] Inconsistency between Scala and Python/Panda udfs when 
groupby with udf() is used
--- The following query will make Scala UDF work, but Python and Pandas udfs 
will fail with an AnalysisException.
--- The query should be added after SPARK-28445.
--- SELECT udf(a + 1), udf(COUNT(b)) FROM testData GROUP BY udf(a + 1);
+SELECT udf(a + 1), udf(COUNT(b)) FROM testData GROUP BY udf(a + 1);
 
 Review comment:
   @skonto, looks all fine except this one. Let's fix and I'll get this in.

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