unde gresesc? de ce nu merg back-reference in sed? vreau ca din momo123 sa transform in 123toto
mures [~]..>>echo momo123| sed 's/momo(.*)/\1toto/g' sed: -e expression #1, char 19: Invalid reference \1 on `s' command's RHS mures [~]..>>echo momo123| sed 's/momo(.*)/\\1toto/g' momo123 mures [~]..>> iar in perl merge brici: mures [~]..>>perl -e '{$a="momo123\n";$a =~ s/momo(.*)/\1toto/ ; printf $a;}' 123toto mures [~]..>> unde gresesc? -- ...and justice for all... _______________________________________________ RLUG mailing list RLUG@lists.lug.ro http://lists.lug.ro/mailman/listinfo/rlug