That did it. Needed to initialize. There were no warnings tho. I get rid of those when I compile. But thanks to everyone who helped.
-----Original Message----- From: Chad Simmons [mailto:[EMAIL PROTECTED] Sent: Thursday, June 10, 2004 3:03 PM To: Mervine, Keith Cc: [email protected] Subject: Re: Problem with an array --- "Mervine, Keith" <[EMAIL PROTECTED]> wrote: You know those warnings you get when you compile? Those are there for a reason. When you're compiling this function it's probably giving you some warnings about the variable lottery being used before it's initialized. Don't ignore this! Lottery is a pointer, it has to point to some peice of valid memory. When it hasn't been initialized it points to some random point in memory, and by iterating over that and/or modifying the data being pointed to you will at best munge you games internal structure causing numerous glitches until the game is restarted. At worst it will cause a crash. Always initialize your data before you use it. And pay attention to warnings your compilier gives you. > void do_generate(CHAR_DATA *ch) > { > int num1, num2, num3; > int pnum1, pnum2, pnum3; > int i; > LOTTERY_DATA *lottery; > > num1 = dice(1,1); > num2 = dice(1,1); //Testing all will be 0,9 > num3 = dice(1,1); > > for (i=0;i<maxLottery;i++) > { > pnum1 = lottery[i].slot1; > pnum2 = lottery[i].slot2; > pnum3 = lottery[i].slot3; > > if (pnum1 == num1 && pnum2 == num2 && pnum3 == num3) > { > info (ch,0,"We have a winner!\n\r"); > } > } > } > > Using GDB I look at pnum1 pnum2 and pnum3 and they turn into something > like 824193073 > > > Any help would be ...well...helpful! ===== -----BEGIN GEEK CODE BLOCK----- Version 3.1 GCS/L/C/O d-(+) s++: a-- C+++$>++++ UBLS++++$ P+++(--)$ L+++>++++ E--- W+>++$ N !o K? w(--) !O M- !V PS+ PE(++) Y+ PGP->+ t+ 5 X+() R(+) tv+@ b++(+++) !DI+++ D G(-) e>+++$ h---() r+++ y+++ ------END GEEK CODE BLOCK------ __________________________________ Do you Yahoo!? Friends. Fun. Try the all-new Yahoo! Messenger. http://messenger.yahoo.com/
