>Hi all,
>
>I'm trying to connect from RPC client to RPC server through a HTTP proxy
>for 2 reasons:
>1. I like to test it because it has to work through a proxy in live
>environment
>2. I like to trace the XML messages send/received!
>
>On the client I have
>
> Properties properties = System.getProperties();
> properties.setProperty("proxyHost", "http://localhost";);
> properties.setProperty("proxyPort", "8080");
> properties.setProperty("proxySet", "true");
> ...
> rpcClient = new XmlRpcClient("http://localhost:9999";);
>
>and I have a server running on port 9999 as well as a http proxy on 8080.
>But the client still does a direct connection to the server - not through
>the HTTP proxy, I can verify that from the proxy logs! I tried to use
>"http.proxyHost" + "http.proxyPort" as well, but it didn't worked!
>
>Any ideas how to get it work?
>
>Martin Skopp
Hi !
I faced exactly the same problem..
The problem is that you have to deal not only with system properties in
order to go through a firewall. You have to add the login/password to the
connection object itself... which means you have to go inside the
implementation of the client.
The way I did it, is by adding so very few lines at the good place of the
XmlRpcClient.Worker :
System.setProperty("http.proxySet","true");
System.setProperty("http.proxyHost",proxyHost);
System.setProperty("http.proxyPort",proxyPort);
con.setRequestProperty ("Proxy-Authorization",proxyAuthorization);
with proxyAuthorization being :
proxyAuthorization = "Basic " + new sun.misc.BASE64Encoder
().encode((user + ":" + password).getBytes());
and con, the UrlConnection object.
Another hint: I didn't use the "http://"; part I specified my proxyHost...
but I don't have any idea if it matters or not.
Finally, if you want, I can send you the source of my XmlRpcClientPlus class
which I derived from the Apache sources of XmlRpcClient. Just ask it
directly (no need to pollute the list with that...)
That's it !
Olivier Sarrat.
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