Re: [Newbie Quetion] How can I check my RPC return value

[Ryan Hoegg]

If the server needs to react to an connection failure during the course 
of an XML-RPC call, it needs to be at the transport layer.  In the 
WebServer class (CVS HEAD) I think this happens in the Connection inner 
class.

I have a servlet wrapper for XmlRpcServer on my to do list somewhere, 
and others on the dev team have mentioned the idea as well.  You should 
have little trouble rolling your own HTTP listener though.  To get you 
started, the XmlRpcServer class has an execute method that takes an 
InputStream and returns a byte[] with the XML response to be sent to the 
client.  Whatever code delivers the InputStream to XmlRpcServer and 
takes the byte[] back to the wire for the client should handle the 
network connection issues.

Hope that helps,
--
Ryan Hoegg
ISIS Networks
http://www.isisnetworks.net/
bagas wrote:

I am sorry but I think your answer did not help . probably because my
previous question confusing .
Here with I'll give you another example hopefully this would be clear .

Suppose I have a Server =

public class TesServer {
  public TesServer() {
       WebServer webserver = null;
       try {
           webserver = new WebServer (7001);
       } catch (UnknownHostException e) {
           e.printStackTrace();  //To change body of catch statement
use Options | File Templates.
           System.out.println("lewat");
       }
       webserver.addHandler("Something",new SomethingHandler());
       webserver.start();
   }
   public static void main(String [] args)
   {
         new TesServer();

   }

}

with a Handler =

class SomethingHandler implements XmlRpcHandler
{
   public Object execute(String method, Vector params)
   {  
      // DO SOMETHING
      //  CONNECTION BROKEN ........ SOMEHOW

      return params;
   }
}
and a Client =

public class TesXmlRPC  {

   public static void main(String[] args) {
       try {
           XmlRpcClient xmlrpc = new
XmlRpcClient("http://10.0.7.222:7001";);
           Vector v = new Vector(1);
           v.add("TEST");
           Vector result = (Vector) xmlrpc.execute("Something.methodX",
v);
       } catch (Exception e) {
           e.printStackTrace();
       }
   }
}
Then I run my Server ...

Then I run my Client ...

When my client "try to" execute 
           
Vector result = (Vector) xmlrpc.execute("Something.methodX", v);  // plz
see TesXmlRPC class

Then the Client connect to server  ..But Before the server produce any
result (so the method above not done yet) .. The connection is somehow
broken ... // see  class SomethingHandler
Then in the Server console screen is written something like this........
java.net.SocketException: Connection reset by peer: socket write error
// this happen because I kill the Client in the middle of executing
"xmlrpc.execute" .
My Question is where can I catch the exception (example :
java.net.SocketException: Connection reset by peer: socket write error
) in my Server class or Handler Class?
Is my question is clear now? If not please ask me for more information .

Thank you ...