Hi,
I have started using xmlrpc-1.2-b1 as a client and am extremely pleased
with it. My thanks to all the developers for their efforts.
When I run my application as a standalone app, all goes well. But when
I run the same as an (unsigned) applet, the following exception is
raised. Yes, yes, I'm aware of applet restrictions and such.
===== my code
import org.apache.xmlrpc.secure.SecureXmlRpcClient;
...
try {
fetchMethod = new SecureXmlRpcClient(fetch);
fetchMethod.setBasicAuthentication(user, passwd);
} catch (MalformedURLException e) {
System.err.println("ERROR: Bad URL " + e);
}
...
// This bombs when called from applet context!
result = (Hashtable) fetchMethod.execute("fetchJob", new Vector());
=====
===== Exception raised
java.security.AccessControlException: access denied (java.util.PropertyPermission
org.apache.xmlrpc.TypeFactory read)
at
java.security.AccessControlContext.checkPermission(AccessControlContext.java:269)
at java.security.AccessController.checkPermission(AccessController.java:401)
at java.lang.SecurityManager.checkPermission(SecurityManager.java:524)
at java.lang.SecurityManager.checkPropertyAccess(SecurityManager.java:1276)
at java.lang.System.getProperty(System.java:573)
at org.apache.xmlrpc.XmlRpc.<init>(XmlRpc.java:201)
at org.apache.xmlrpc.XmlRpcClient$Worker.<init>(XmlRpcClient.java:325)
at org.apache.xmlrpc.XmlRpcClient.getWorker(XmlRpcClient.java:234)
at org.apache.xmlrpc.XmlRpcClient.execute(XmlRpcClient.java:160)
...
=====
The offending line is in ./org/apache/xmlrpc/XmlRpc.java line 201. The
following change to XmlRpc() seems to fix the problem for me. For the
record, I'm using java 1.4.2_04 on linux. I have not tested on other
platforms.
===== XmlRpc.java
protected XmlRpc()
{
// System.get...() always returns null on my box anyway!
// this(System.getProperty(TypeFactory.class.getName()));
this((String) null);
}
=====
I admit that my workaround is too crude, but can someone offer a better
solution that is more acceptable for all? Can someone help?
- Raja
